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» SmaugMuds » Codebases » LoP Codebase » bribe_trigger
Forum Rules | Mark all | Recent Posts

bribe_trigger
< Newer Topic :: Older Topic > question

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Post is unread #1 Oct 12, 2011 2:46 am   Last edited Oct 12, 2011 2:47 am by Matteo2303
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Matteo2303

GroupMembers
Posts86
JoinedAug 25, 2003

 
In mprog_bribe_trigger there is:

      /* Go through once to see which we should use */
      onprog = 0;
      for( mprg = mob->pIndexData->mudprogs; mprg; mprg = mprg->next )
      {
         ++onprog;
         if( ( mprg->type == BRIBE_PROG ) && ( uamount >= atoi( mprg->arglist ) ) && ( amdiff == 0 || ( uamount - atoi( mprg->arglist ) ) < amdiff ) )
         {
            amdiff = ( uamount - atoi( mprg->arglist ) );
            useprog = onprog;
         }
      }

      /* Go through it again and use the closest bribe program to the amount */
      onprog = 0;
      for( mprg = mob->pIndexData->mudprogs; mprg; mprg = mprg->next )
      {
         if( ++onprog != useprog )
            continue;

         if( ( mprg->type == BRIBE_PROG ) && ( uamount >= atoi( mprg->arglist ) ) )
         {
            increase_gold( mob, uamount );
            mprog_driver( mprg->comlist, mob, ch, obj, NULL, false );
            if( obj )
               extract_obj( obj );
            break;
         }
      }


I don't know but, is possible declare another mprg and make:

MPROG_DATA *sprg = NULL; 
      /* Go through once to see which we should use */
      for( mprg = mob->pIndexData->mudprogs; mprg; mprg = mprg->next )
       if( ( mprg->type == BRIBE_PROG ) && ( uamount >= atoi( mprg->arglist ) ) && ( amdiff == 0 || ( uamount - atoi( mprg->arglist ) ) < amdiff ) )
         {
            amdiff = ( uamount - atoi( mprg->arglist ) );
            sprg = mprg;         
         }

if ( sprg )
{
       increase_gold( mob, uamount );
       mprog_driver( sprg->comlist, mob, ch, obj, NULL, false );
       if( obj )
       extract_obj( obj );
       break;
}

Post is unread #2 Oct 26, 2011 8:33 pm   
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Remcon

GroupAdministrators
Posts1,946
JoinedJul 26, 2005

 
Haven't tried, but should be able to. Minus the break in the part your adding since it isnt in a for loop

Post is unread #3 Oct 31, 2011 3:04 am   Last edited Oct 31, 2011 3:08 am by Matteo2303
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Matteo2303

GroupMembers
Posts86
JoinedAug 25, 2003

 
Yeah, minus "break".
My bad.

Bye
mat

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